• Our booking engine at tickets.railforums.co.uk (powered by TrainSplit) helps support the running of the forum with every ticket purchase! Find out more and ask any questions/give us feedback in this thread!

General Knowledge Quiz

341o2

341o2

Established Member
Joined
17 Oct 2011
Messages
1,902
I'm referring to one particular club.
The things we have to do to appease the youth of today
 
Sponsor Post - registered members do not see these adverts; click here to register, or click here to log in
R

RailUK Forums

341o2

341o2

Established Member
Joined
17 Oct 2011
Messages
1,902
That is the answer I am looking for, and to fill in the other half of the question, Juventus FC, usually known as Juve based in Turin, is one of Italy's leading clubs, although it did have a period of relegation following the Capello scandal. I wonder whether JB heard of the name and thought it useful for his Evallonian youth group. Juventus FC was originally founded by a group of Turin students, at first an athletic club, becoming a football club within a few years

Your floor
 
A

A Challenge

Established Member
Joined
24 Sep 2016
Messages
2,823
That looks like it is the values of a quadratic, however I can't find one that fits beyond two points (x^2+11/12). I'm going to make an educated guess at point 3 being 1.6, for which working can be provided if needed, and could use the same method to get the others if that turns out to be correct.
 
DaleCooper

DaleCooper

Established Member
Joined
2 Mar 2015
Messages
3,513
Location
Mulholland Drive
A Challenge said:
That looks like it is the values of a quadratic, however I can't find one that fits beyond two points (x^2+11/12). I'm going to make an educated guess at point 3 being 1.6, for which working can be provided if needed, and could use the same method to get the others if that turns out to be correct.
Click to expand...
1.6 is correct for the third term, I'll be surprised if your method provides the other two.
 
A

A Challenge

Established Member
Joined
24 Sep 2016
Messages
2,823
I'm not sure whether you've worked out my method, but I think 3.2 is almost correct, I'm getting awrt 3.188 (2dp) - no clue for the last one though, it appears to reverse direction (start going up rather down)
 
DaleCooper

DaleCooper

Established Member
Joined
2 Mar 2015
Messages
3,513
Location
Mulholland Drive
A Challenge said:
I'm not sure whether you've worked out my method, but I think 3.2 is almost correct, I'm getting awrt 3.188 (2dp) - no clue for the last one though, it appears to reverse direction (start going up rather down)
Click to expand...
Yes 3.2 is almost correct and 3.188 is even nearer but I think you need to approach this differently.
 
A

A Challenge

Established Member
Joined
24 Sep 2016
Messages
2,823
I can get closer - 51/16 - but that is, if correct, hard to carry on to the 9th term - the quadratic passes through more points, but that is the problem!

It's not second differences either, that produces 3rd term = 19/12, and an alternative difference calculation will produce fifth term = 3.05.

Geometric series, however, seems to produce something workable, given the constant common ratio between all of the pairs you've given (using a=1, r=1.25), but it doesn't work across the gaps.

If you instead try a=0.790569415 and assume you missed the first term (ie that a is the 0th term, it just makes the maths easier), then this gets you r=1.260055656 with a regression value of 0.9999843013 (almost correct).

Using an alternative regression model of a*(x^b) you get a regression of close to 0.952 - even further out.
 
DaleCooper

DaleCooper

Established Member
Joined
2 Mar 2015
Messages
3,513
Location
Mulholland Drive
A Challenge said:
I can get closer - 51/16 - but that is, if correct, hard to carry on to the 9th term - the quadratic passes through more points, but that is the problem!

It's not second differences either, that produces 3rd term = 19/12, and an alternative difference calculation will produce fifth term = 3.05.

Geometric series, however, seems to produce something workable, given the constant common ratio between all of the pairs you've given (using a=1, r=1.25), but it doesn't work across the gaps.

If you instead try a=0.790569415 and assume you missed the first term (ie that a is the 0th term, it just makes the maths easier), then this gets you r=1.260055656 with a regression value of 0.9999843013 (almost correct).

Using an alternative regression model of a*(x^b) you get a regression of close to 0.952 - even further out.
Click to expand...

The maths is impressive but it's leading you up a blind alley. This series might be described as practical.
 
A

A Challenge

Established Member
Joined
24 Sep 2016
Messages
2,823
If I didn't know about the 1.6 bring correct, I would guess 1.5, 3 and 6 then (seems good numbers for sizes of Allen keys or something), so if 1.6 is correct then that explains to me @xotGD's set of numbers. If I can't solve it using maths, I'm going to be a bit out of my depth here I think, as I have no idea where to start otherwise, so, except for any amazing brainwaves (that common ratio is strange), I'll wait for the answer to be revealed, and assume my finding of 1.6 being correct as a happy coincidence and 1.188 (51/16 doesn't seem 'practical' as you say) even moreso.
 
xotGD

xotGD

Established Member
Joined
4 Feb 2017
Messages
6,075
DaleCooper said:
Yes it is. To clarify: the two series are ...
1.00, 1.25, 1.60, 2.00, 2.50, ?, 4.00, 5.00, ?, 8.00
1.00, 1.25, 1.60, 2.00, 2.50, 3.20, 4.00, 5.00, ?, 8.00
Click to expand...
I'm assuming it is the size range of some sort of equipment. Maybe knitting needles?

So I'll take a punt that the missing number in the bottom series is 6.00.
 
DaleCooper

DaleCooper

Established Member
Joined
2 Mar 2015
Messages
3,513
Location
Mulholland Drive
xotGD said:
I'm assuming it is the size range of some sort of equipment. Maybe knitting needles?

So I'll take a punt that the missing number in the bottom series is 6.00.
Click to expand...

I don't know much about knitting needles but as far as I'm aware they don't come in those sizes. The 9th term is the same in both series but it is not 6.00. Here's a clue:
fluke-2279339-fuse.jpg
e
 
N

Nick_C

Member
Joined
30 Jan 2020
Messages
34
Location
Hampshire
DerekC said:
There was a lot more to the Polish contribution than that. The Poles under the leadership of Rejewski broke the first version of the Enigma machine using their "Bomby" which was the intellectual ancestor of the Bletchley Park "Bombe" even though the "Bombe" was much more advanced. In one of the key moments of the war (before it even started) in July and August 1939 the Poles handed over a copied version of the Enigma, the design of the Bomby and the "Zygalski sheets" which also formed a key part of their methods of decryption. This got Turing and Bletchley Park off to a flying start.
Click to expand...

There is a memorial to Henryk Zygalski in Chichester crematorium - definitely one of the real 'unsung heroes' of the war.
 
A

A Challenge

Established Member
Joined
24 Sep 2016
Messages
2,823
That's a fuse - I thought fused items were meant to have the fuse value written on them but I can't find one on the plug in the electrical socket closest to me and can't really unplug anything else in the room!
 
DaleCooper

DaleCooper

Established Member
Joined
2 Mar 2015
Messages
3,513
Location
Mulholland Drive
xotGD said:
I only know 3 Amp and 13 Amp, so I give up!
Click to expand...
Now you know another one.

A Challenge said:
That's a fuse - I thought fused items were meant to have the fuse value written on them but I can't find one on the plug in the electrical socket closest to me and can't really unplug anything else in the room!
Click to expand...
I thought the picture was a giveaway, apparently I was wrong.
 
You must log in or register to reply here.

Top