TheNewNo2
Member
I personally proved it by induction on the number of seats. Then I realised you could go more general and instead of proving that the last one had a probability 1/2, you can instead prove that the jth person has probability (n-j+1)/(n-j+2) of getting their own seat (by induction on j), and then the last person is just a special case of that.
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I also rather liked the one from two weeks ago:
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I also rather liked the one from two weeks ago:
There is a long straight single lane road, with all traffic going in the same direction. If each car travels at a unique speed, and overtaking is not possible, how many groups of cars will the traffic separate into over time?
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