Yes, sorry. I lost that when I edited the post. For a given value of R, as V increases I decreases to transmit the same power.Not quite! For a fixed resistance, as V gets larger, I gets larger too.
I think what you meant is that for a fixed power, the current is less and so the losses are less. Power= V*I so, if V is greater then, for the same power, I is less. The (resistive) losses are I^2 * R, so increase with the square of the current. (With alternating current the impedance is not just the resistance, but that's another matter!)